Propeller Design

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Tip speed is not D * n. Tangential tip speed is r * omega (radians/ second). If r is in feet, tangential velocity is feet per second. If r is meters, then it is in meters per second. But, you have to factor in forward velocity in the same units, too. Prop tip speed = square root [(forward velocity)^2 + (tangential velocity)^2].

Lets say you are at 25,000 feet going 450 mph in some wonder chariot. You have an 11 foot diameter propeller and your engine is turning 3,000 rpm.
The prop reduction gear is 0.42 : 1.

1) 450 mph = 660 feet/ second.
2) Propeller rpm = 3,000* 0.42 = 1,260 rpm, so Omega = 131.947 radians/ second.
3) Tangential speed = (11 / 2) * 131.947 = 725.708 feet/ second.
4) Prop tip speed = square root (660)^2 + (725.708)^2) = 980.926 feet/ second.
5) At 25,000 feet on a standard day, the speed of sound is 1,014.3 feet/ second.
6) So, the tip speed is (980.926 / 1,014.3)= Mach 0.97. Not very likely since the tip speed is so close to M1.

I'd feel a LOT better about the hypothetical situation if the tip speed were around Mach 0.87 or so. For our aircraft /prop / engine combination, our forward speed would have to drop to 342.5 mph to get the tip speed to M 0.87.

Alternately, we could still make Mach 0.92 if everything was the same except our prop was 10 feet in diameter and we could put up with a tip speed of M0.92.
 
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Not being pedantic and that doesn't matter since the prop tip goes in a complete circle and the average tip speed comes right when the tip is horizontal.

Some people might actually want to know how to calculate propeller tip speed. For those that don't, just ignore the math.
 
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When the Osprey has its wings at an AOA of say 45°, are the prop tips going at the same absolute speed when they are horizontal?
Now with your chariot with only a few degrees difference in pitch b/n prop axis and path it won't be much, but if one is being pedantic it does make a difference.
 
For a tilt-rotor, yes, it can matter. For a standard piston propeller aircraft, no.

The thing is, when the tilt rotor is in airplane mode and at its top speed, then the angle does NOT make a difference since the rotor is at 90° to the flight direction vector just like a standard propeller. When the rotor is at 45°, the forward speed has dropped enough to not matter (as far as supersonic prop tips go) as long as the tip speed is subsonic in fast airplane mode.

So, while we CAN calculate it, it doesn't make a real-world difference in low-speed transition mode. Early in the tilt rotor life, it DID make a difference. I was flying an Arizona in the mid-1990s when a Marine tilt rotor flown be Marines was in fast airplane mode near Marana, AZ and the pilot decided to ignore limits and transitioned to vertical rotor position when he was going too fast. When he pulled up to slow down, he stalled the rotors at low altitude and never recovered. He crashed just off the end of the runway at the old Marana airport. After that, EVERYONE who flew trilt rotors knew the limits were there for a reason.

Now, the flight mode software won't let you do that.
 
Nice post but shouldn't it be "fewer blades is more efficient"?
I just re-read my post, and thought, "How did I do that? It's exactly backwards. I wonder if anyone caught that."

The very next thing I read was your post. Fixed it in the original, thanks.
 
Helicopters are perverse beasts that can go backwards and forwards at the same time. For this reason, no helicopter has ever gone supersonic. And that's why I like tilt-rotors when you absolutely have to go straight up from the deck.
 
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I'll leave it to others to argue over whether you're being pedantic.

You have correctly observed that the path of the prop tip is a helix. In my defense, tangential tip speed is proportional to D * n, you just have to multiply by Pi and divide by 60 to get the units to work out.

I think we can all see that if tip speed is the root of the sum of the squares of tangential speed and flight path speed, then if tip speed has to stay below a fixed number (Mach 1), then as flight path speed gets big, tangential speed has to get small. When I said to keep the tip speed somewhere between 750 and 950 fps, that was overall speed, since I hadn't specified a flight path speed...meaning, of course, you might design a prop differently for the same engine if you were putting it into a fast fighter or a slow transport.

Here's my favorite example, the Tu-114 on its record run. Flight speed is 545 mph or 799 fps. Engine rpm is 9250, gear reduction is 11.33:1, prop rpm is about 815 rpm. The props are 18.3 feet in diameter, so tangential speed is 18.3 * 815 * Pi / 60 = 781 fps. That means tip speed is (799 ^2 + 781 ^ 2) ^ 0.5 = 1117 fps. At 8,000 meters (26,000 feet), that's right around Mach 1.1! And that's why cruise was at 480 mph and 735 prop rpm, I'd hate to see the fuel flow on those record runs. This is also why the Tu-114 and all the other Tu-95 variants were the loudest airplanes in history (although the XF84-H "Thunderscreech" might have given them a run for their money).

Another way to think about it is that at 815 rpm and 545 mph, each blade completes one revolution as it moves forward every 59 feet, over 3 times the diameter of the prop. The total distance the tip would travel along the helical path would be "only" 82 feet.
 
All fighter props (that I'm aware of) are driven via a gear reduction unit. I would imagine the drive ratio would also play a big part in determining what type of prop to use. Greg's Airplanes and Automobiles (on Youtube) has a good video explaining the different propeller types, and why they were used...
 

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