billswagger
Airman 1st Class
- 256
- Mar 12, 2009
Ad: This forum contains affiliate links to products on Amazon and eBay. More information in Terms and rules
The reduction gearbox will reduce the rotational speed of the propeller in relation to the powerplant. This is to prevent the tips of the prop from exceeding a mach number rotational speed, as at that point it will become significantly less efficient.Is it the propeller that spins twice for every time the engine revolves once, or is it the other way around?
i've also seen blower gear ratios for the supercharger that read something like 8.8:1 or 9.6:1. So i also wondered how and what those ratios correspond to
This is a more technical question.
I know what the reduction gear is for, but when reading about some aircraft engines i sometimes see the ratio published as 2:1 or some other figure.
So i wondered if anyone knew how the ratio is factored into the rotations of the engine and propeller.
Is it the propeller that spins twice for every time the engine revolves once, or is it the other way around?
While i have your attention, i've also seen blower gear ratios for the supercharger that read something like 8.8:1 or 9.6:1. So i also wondered how and what those ratios correspond to.
I've tried looking it up briefly, but nothing really touches on the ratios instead they focus on the engineering aspect of the engine.
thanks
Bill
Somewhere, somebody, probably made a set up where the prop turns faster if only to say they did it.
= 6289 prop speed??
Shouldn't a reduction gear always reduce the output revs no matter which number in front of the ":"?