I figure that the area of a circle is: A = pi*(r)^2, and the formula for a cylinder is

- V = (area of the base)*(h)
- V = (pi(r)^2)*(h)

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- Thread starter Zipper730
- Start date

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I figure that the area of a circle is: A = pi*(r)^2, and the formula for a cylinder is

- V = (area of the base)*(h)
- V = (pi(r)^2)*(h)

Theoretically. In practice there is a boundry layer effect on the wall of the pipe so the flow is slightly greater than 4x.

I figure that the area of a circle is: A = pi*(r)^2, and the formula for a cylinder is

Correct?

- V = (area of the base)*(h)
- V = (pi(r)^2)*(h)

- Thread starter
- #3

Look at the equation. You have chosen "doubles" which means two times as big and the result is "four" which is two squared.

I figure that the area of a circle is: A = pi*(r)^2, and the formula for a cylinder is

Correct?

- V = (area of the base)*(h)
- V = (pi(r)^2)*(h)

If it was as simple as the OP there wouldnt be a science of fluid dynamics. For example, the diameter isnt a constant, when the fluid pressure is increased the diameter of the pipe increases, but this is the fluid exerting a force on the pipe which leads to the boundary effects you mentioned. There is all sorts of "stuff" about viscosity, pressure velocity surface condition etc, just as there is with gases

- Thread starter
- #7

And if you correct for reynold's numbers you end up with the boundary layer not scaling up too much...

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