Fascinated
Airman
- 18
- Apr 18, 2013
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From this table, for the 1/16 B-17, the scale factor would be sqrt(1/16) = 1/4, converting 187 mph to 46.75 mph scale speed. While perhaps still a bit slow, this is much more reasonable and can be more closely approximated. The Harding article uses a power/drag calculation and produces a factor of approx. 0.3, or 55.4 mph, a very similar result.The B-17 cruised at 187 mph. In scale RC model meets some of the judges are wanting the planes to fly at scale speeds too. So for the 1:16 B-17 I built the scale speed would be a bit under 12mph. Instead the model flew at about 80mph.
Fascinating, though at this point in time, about half of it kind of absorbed into my mind. It's about 10:30 over here and I'm fatigued.Scaling Laws by Dave Harding offers a good explanation and derivation of scaling factors.
What you have is almost exactly an RG Cardinal with a 172 engine, its empty weight increased approx 200 lbs and its drag increased by 10-15%, probably for performance reasons mandating a reduced gross weight. Can you spell "lead sled"?Or if you stick the wing of a 210 on a 172 how much of your payload do you give up to stay within gross weight?
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Like trying to reduce a multi-variable, multi-step design process down to a simple rule of thumb? You might be right about that. "Ain't no free (or even cheap) lunch, lad."I feel like something's wrong with my interpretation
You don't mean "Its complicated" by any chance?Like trying to reduce a multi-variable, multi-step design process down to a simple rule of thumb? You might be right about that. "Ain't no free (or even cheap) lunch, lad."
Cheers,
Wes
Look, I'm curious if my interpretation was correctLike trying to reduce a multi-variable, multi-step design process down to a simple rule of thumb?
Naw, "complicated" is too simplistic and imprecise a term. "Multi-variable, multi-step" sounds more impressive, don't you think? Maybe I'll add "muti-faceted" as well, just for the effect.You don't mean "Its complicated" by any chance?
I spent my working life on the various ramifications of the Iron-Carbon equilibrium diagram. Anyone can produce this diagram and every time I tested products for some reason there were exceptions to it, simply because you never get just iron and carbon you get a whole lot of other "stuff" too, that's when it gets complicated. As a rule of thumb any ton of Iron/Carbon will break your toes if you don't wear safety boots,, hope that helps.Naw, "complicated" is too simplistic and imprecise a term. "Multi-variable, multi-step" sounds more impressive, don't you think? Maybe I'll add "muti-faceted" as well, just for the effect.
Cheers,
Wes
There are no rules of thumb, there are rules and laws of physics, aerodynamics, thermodynamics, thermoconductivity, metallurgy and dozens of other fields all of these impinge on each other. In every discussion you look for a "killer" number or rule of thumb. Life isn't like that.Of course, however I'm mostly looking at rules of thumb. So this seems like a solid step.
My main issue is to make sure that my understanding was correct: It's possible to read something and misunderstand. Happens to everybody now and then far as I know
Jeez! Who do I gotta blow to get a straight answer1. Fuselage length is to the cube law: x^3
2. Wingspan scales to the power of x^3.2238. On that note, does this include the fuselage in the span, or just left wing & right-wing minus fuselage?
3. Spar-stress for equal g-load increases by 2.25 for every doubling in size (i.e. the mean of x^3.2 and x^2)?
4. Wing Loading increases by 2.25 for the doubling of A/C weight; stall speed increases by 1.5?
- Fuselage length is to the cube law: x^3
- Wingspan scales to the power of 3.2238
- Does that include the fuselage in the span, or does that just cover each wing?
- Spar stress for equal g-load increases by 2.25 for every doubling in size (basically the mean of x^3.2 and x^2)
- Wing Loading increases by 2.25 for the doubling of A/C weight; stall speed increases by 1.5?
That was a possibility that I had been concerned with. I derived the figures based on what I interpreted out of the pdf file: Scaling Laws by Dave Harding.I don't understand how you arrived at some of these values.
Of course, that I get fine. And if you're scaling for volume, then K^3, and if everything doubles 2^3 = 8.If 'K' is your scaling factor, all lengths scale the same, K^1. If you are scaling x 2, then fuselage length, wingspan, are all x 2. (2^1 = 2)
Well, as I understood it, wing-loading is the weight of A/C divided by the wing-area. That kind of left me scratching my head.I also don't understand what you are asking by "wing loading". Do you mean you are doubling the A/C weight while keeping all else the same?
That I graspedIf you are reading this from the PDF, then note that the table at the end of the article lists the scaling for SIZE doubling. He argues that weight increases faster than volume, by K^3.22.
So, basically all proportions being equal the wing loading keeps increasing by K^1.22 instead of K^1, and flying speed increasing to the square-root of this.This results in the wing loading increasing by K^1.22 (The weight increases by K^3.22, the area increases by K^2. Weight / Area = K^3.22/K^2 = K^1.22) But again, this is for a doubling of SIZE, not weight.
If I recall doubling the weight would cause the stall speed to increase to the square root of 2. So a 10,000 pound plane with a stall speed of 100 knots, would stall at 141.4 knots if it's weight was increased to 20,000 pounds (same wing area).I think you are reading the stall speed correctly, except again, you are not doubling the weight.
I'm not sure where his (0.0001*span^3.2238) came from. He has plotted weight (oz.) vs. span (in.) on a log-log plot. So I think he has calculated the slope to derive that relationship. On his line, 100 oz. crosses at about 64 in. So, (0.0001*64^3.2238)~=66.5. Ok, but I think the coefficient will only be correct for this set of units (ounces vs. inches).I was just curious about weights and amount of lift required: According to the text: The scaling for span seemed to increase by K^3.2238. Figure 3 on the second page listed (0.0001*span^3.2238).
K=1.5, right? So K^1.22 = 1.5^1.22 = 1.64 approx. Your initial wing loading was 25 * 1.64 = 41, pretty much what you got the first way. Unless I'm missing something. I really have to write this all down carefully to keep it straight.So if I was to increase the wingspan by 1.5, which is around 59'3", weight would increase (all things being equal) to around 23984 (A/C weight * 1.5^3.22), wing-area to a hair short of (wing area * 1.5^2), and a wing-loading of 40.93. These numbers don't look right... if K^1.22 was right I'd have a wing-loading of 88.7 right?