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I thinkI don't see how weight can "have nothing with dive speed and dive acceleration"
Weight is literally the reason why you can dive at higher speed and higher acceleration than you can fly horizontally. When diving, weight does have a force vector in the direction of travel, the steeper the dive angle, the bigger this force component will be, basically increasing your "thrust"
Perhaps you wish to explain why the limit dive speeds of the Mustang and the P-47 are the same. And why the F6F and F4U are 'slower' in dive than the Mustang? Greg's point was that 'weight' per se is not the primary factor for achieving high speed in a dive.I don't see how weight can "have nothing with dive speed and dive acceleration"
Weight is literally the reason why you can dive at higher speed and higher acceleration than you can fly horizontally. When diving, weight does have a force vector in the direction of travel, the steeper the dive angle, the bigger this force component will be, basically increasing your "thrust"
ROFLMAOThe engine has to pump air out of the cylinders through the turbine. I am not totally into turbochargers. They may be more efficient than engine driven superchargers. They still use significant power
Ok, I don't have exact number so i will use this ">" symbol to explain "greater" , more ">" symbol illustrate more magnitude of greaterPerhaps you wish to explain why the limit dive speeds of the Mustang and the P-47 are the same.
same as P-47, they are draggier than P-51, but they don't have enough additional mass to compensate to that in a diveAnd why the F6F and F4U are 'slower' in dive than the Mustang?
In a vacuum then sure , being heavier doesn't matter. But in atmosphere, being heavier basically give you more "thrust" to overcome the drag when diving.Greg's point was that 'weight' per se is not the primary factor for achieving high speed in a dive.
P-38 control surface at lock up at high speed as far as i know, and it probably much draggier than P-47 due to the twin boom as wellAnd explain why the P-47 is faster in dive than say a P-38 (which weighs more).
Read your Eric Brown. A P-47 had a "tactical Mach number" of 0.71. A P-38's is 0.68. The Bf109 and Fw190 were 0.75, and the P-51 0.78. The P-47 may have better acceleration in a dive, but the Mustang can achieve a higher speed, safely anyway. Brown described Spitfires as "easily controlled" up to Mach 0.84. The Spitfire would have less acceleration in the dive, and the highest ultimate speed.P-38 control surface at lock up at high speed as far as i know, and it probably much draggier than P-47 due to the twin boom as well
I think the Yak can sit this one out.pbehn,
Obviously, not the Yak-3.
You have forced me to check my sources.If all of the above aircraft were to fly at their maximum speed at 30,000ft then dive vertically down, which would break up first which would reach the highest speed and how long would it take?
MiG-31BM,Ok, I don't have exact number so i will use this ">" symbol to explain "greater" , more ">" symbol illustrate more magnitude of greater
P-47 vs P-51
Because top speed is reached when thrust = drag
P-47's drag >>> P-51's drag
P-47's engine power at sea level >> P-51's engine power at sea level
=> P-47's horizontal speed at sea level < P-51's horizontal speed at sea level
P-47 engine power at 30k ft >>>>P-51 engine power at 30k ft
=> P-47's horizontal speed at 30 kft > P-51's horizontal speed at 30 kft
When diving , the mass of the aircraft add into the "thrust", because gravity has a component in direction of travel when aircraft is diving
and since P-47 weight >> P-51 weight
it is not a big surprise that it would be enough to close the gap in drag
same as P-47, they are draggier than P-51, but they don't have enough additional mass to compensate to that in a dive
and their engine output at altitude is less than P-47 as well
In a vacuum then sure , being heavier doesn't matter. But in atmosphere, being heavier basically give you more "thrust" to overcome the drag when diving.
Let me put it this way. If we have a piece of paper 4*4 cm, and a piece of metal 4*4 meter, then obviously the piece of metal will have more drag due to much higher surface area.
However, when we drop them, the piece of metal will still fall to ground much faster than the piece of paper
P-38 control surface at lock up at high speed as far as i know, and it probably much draggier than P-47 due to the twin boom as well
So?. Even if iam wrong, it still better to say what i think, so that people can correct my mistake. I would rather be a fool once than remain silent and be a fool foreverMiG-31BM,
FYI you are arguing aerodynamics with a guy who has both a BS and a Masters in Aerodynamics…
Cheers,
Biff
This is what still kinda confuse me till now.. A P-51H at 487mph is running on 150 octane fuel and water injection. On 100/130 octane, it should be somewhat faster than the P-51D shown.
115/145 and 90''In this chart, is the F-51H running with 130 octane or 150 octane fuel?
Thank you for helping me forget all that I learned while studying for my MS in Aero. While I desparately clear the cobwebs trying to re-learn the CDparasite of paper and cannonballs I usually go look at the Wing first for 'hidden clues'. Maybe you should also. While strolling through those references, seek insight on Drag Rise as CDp varies with Mach No. As you peruse through CDp vs Mcr (and beyond) seek clues regarding thickness to Chord ratio and location of Max T/C for each of the wings. Seek further elucidation on the % of Drag contribution of the Wing v Fuselage v Empennage.Ok, I don't have exact number so i will use this ">" symbol to explain "greater" , more ">" symbol illustrate more magnitude of greater
P-47 vs P-51
Because top speed is reached when thrust = drag
P-47's drag >>> P-51's drag
P-47's engine power at sea level >> P-51's engine power at sea level
=> P-47's horizontal speed at sea level < P-51's horizontal speed at sea level
P-47 engine power at 30k ft >>>>P-51 engine power at 30k ft
=> P-47's horizontal speed at 30 kft > P-51's horizontal speed at 30 kft
When diving , the mass of the aircraft add into the "thrust", because gravity has a component in direction of travel when aircraft is diving
and since P-47 weight >> P-51 weight
it is not a big surprise that it would be enough to close the gap in drag
same as P-47, they are draggier than P-51, but they don't have enough additional mass to compensate to that in a dive
and their engine output at altitude is less than P-47 as well
Oh, how could I lose sight of that comparison while discussing Drag of WWII fighters?In a vacuum then sure , being heavier doesn't matter. But in atmosphere, being heavier basically give you more "thrust" to overcome the drag when diving.
Let me put it this way. If we have a piece of paper 4*4 cm, and a piece of metal 4*4 meter, then obviously the piece of metal will have more drag due to much higher surface area.
However, when we drop them, the piece of metal will still fall to ground much faster than the piece of paper
Both the P-47 AND P-38 experienced 'nose tuck' at or near MCr in which dive recovery was delayed until reaching higher density altitude. And for the record, the CDp of the P-38> P-47 but reached Mcr at or near 0.68M. P-38, F4U and F6F all had CDp nearly the same.P-38 control surface at lock up at high speed as far as i know, and it probably much draggier than P-47 due to the twin boom as well
Maybe in a combat situation pilots got into a situation that they couldnt get out of. 25,000ft is 4.7 miles and at 480MPH you are doing 1 mile every 7.5 seconds, if controls lock up at high speed when do you have to start pulling out of a dive steeper than 45 deg.You have forced me to check my sources.
In early 1944, the Americans were losing escort fighters when they dove down on Germans at high speed. I presume their controls locked up. I assume bomber interceptor interception took place at a bit over 30,000ft. Brown's terminology is interesting. He talks about tactical (manoeuvring) and critical (loss of control) Mach numbers. The tactical Mach numbers of the P-38H and the P-47C were 0.68 and 0.71, respectively.
I am a bit puzzled by all this. Roland Beamont tested Hawker Typhoons by diving from 30,000ft, I think at around 45°. Their controls locked up. It appears to me that a Typhoon would have difficulties doing much more than 300mph at 30,000ft. At around 15,000ft, the speed of sound would increase sufficiently to drop the Mach number to the point where the aircraft could be controlled. Beamont died of old age in 2001.
I don't understand why the Thunderbolts and Lightnings were unable to pull out. If they pull out at 15,000ft, they would be vulnerable to Fw190s. Otherwise, they slowly or quickly (respectively) climb back up the bomber altitude, or they fly home. It would be wise for the Thunderbolt to get his ass up above 25,000ft.
Diving from top speed at 40,000ft, the stripped and instrumented SpitfireXIs started to gently shake at Mach 0.83. Does this translate to tactical Mach number?
In early 1944, the Americans were losing escort fighters when they dove down on Germans at high speed. I presume their controls locked up. I assume bomber interceptor interception took place at a bit over 30,000ft.