Ballpark estimate of the effects of two 150 gallon tanks on a P-47 D30's speed at 20000ft
using this simulation tool. (Simulated the D30 since I had that modeled already).
Baseline: Assuming a cruising type power setting yielding 310 mph (499 km/h) at 20000 ft in clean configuration.
Then adding effects of drop tanks with drop tank parasitic drag estimated as Cd0=0.33*d/l as per formula 21 on page 6-16 in Hoerner's book Fluid Dynamic Drag.
Speed using same power setting as clean, but now with two 150 gallon drop tanks added at 6100 m this gives a 455.8 km/h TAS. This is taking both parasitic and induced drag due to added fuel weight into account.
So 500-455.8=44.2 km/h or 27.5 mph with both parasitic and induced drag accounted for (If only taking the parasitic drag into account then the speed loss is only 11.5 mph).
But this is only for the drop tank drag and does not including drag and weight of rack (Don't have that info).
Say that this deducts an additional 4 mph then the total speed loss at 20000 ft would then be around 27+4=31 mph.
Again, only a ballpark estimate, but seems reasonable if the P-51 (which is a much cleaner design with a lower span loading, i.e. lower induced drag) loses around 40 mph carrying a couple of 110 gallon wing tanks.
Anyway, in summary, I would say that this ballpark estimate shows that assuming a speed loss of only 10 mph when adding a couple of 150 gallon tanks to a P-47 would be way too optimistic.