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Btw, I am still waiting for the references you claim to possess Bill.
Sore, what I was asking was what the charaterisics of the stick forces were at critical mach. As I understand it, elevator control loss comes in 2 possible forms 1: excessve control forces, 2: being blanked by turbulence with controls still movable.
You are correct
Which is the case for the Me 262? (if it's the former, boosted controls would allow the elevator to work as it did in the F-86 -granted the F-86's tailplane had a higher Mach number as well)
I believe number 1.
And you never answered my question from post #195.
Soren tends to avoid questions that require "i don't know"
That's very interesting on the Me 163 Delcyros. I would think that the thick root section (14% -not sure about sweep-) would be too thick, not to mention the wooden wing construction. (not to mention the trim problems of tailless aircraft in the transsonic regionand possible issues with the LE slots at such speeds) Besides the much breater thrust available at these speeds, I think the Me 163 would be less likely sucessfully perfrom this feat than the Me 262.
I actually am of a different opinion. I believe the 163 had a better chance depending on its' ability to ovecome CM ac change as shock wave moved the ac rearward. I have zero opinion of the 163 in the transonic to supersonic stabilty and control.
And Bill, Data for the Me 262's tailplane airfoil would be interesting, but I immagine that's going to be difficult to find. (also not there was no sweepback to the tailplane, it just had LE taper, there was a ~20 degree swept-back version used on the HG I/II though)
It's nr.2 KK, the elevator trim tabs are still movable but emersed in turbulence thus ineffective. But like I've been saying from the beginning not the whole horizontal stabilizer is emersed in turbulent airflow, only the rearest part where the control surfaces are located, and again because of the shockwave forming at the LE of the stabilizer fin. So trimming the taiplane will work. Thus the only way to change pitch attitude in transonic flight is to trim the tail plane, like Mutke did.
BS Alert. The elevator and trim tabs are not only movable but not immersed in turbulence - unless you have aspecific reference to the contrary. where is it? If the shock wave is at the LE, there is a shockwave at the TE. The flow in between is reasonably laminar and supersonic - the stupid tail in this condition has gone SUPERSONIC Soren. What else don't you understand about supersonic flow over an airfoil???? Freestream in front of tail is ALWAYS SUBsonic, Shockwave starts at leading edge. At Trailing edge the flow transforms from supersonic back to SUBsonic. Freestream airflow aft of the airfoil is also ALWAYS SUBsonic!!
Same as a frapping boattail, round nose or spitzer form.. for a supersonic bullet
If it were option nr.1 you'd read it in the a/c manual as the control forces will increase gradually along the speed range, but no such thing is mentioned.
BS Alert. The only thing that influences stick forces is that CMac and/or trim drag undergoes a step change due to either wake turbulence, compressibility over the control surface or movement of the ac in transonic flow.
What is said is that the controls remain light throughout the speed range, even at very high speed. As a matter of fact I've never heard or read about high stick forces in the Me-262, from all that I have read about the a/c the controls were light and well harmonized at all speeds.
Bill,
Here are MY sources:
Go here: http://www.zenoswarbirdvideos.com/Images/Me262/ME262PILOTDEBRIEF.pdf
Read under flying characteristics, from Me-262 test pilot Hans Fey:
"There is no flutter while diving. Fay conjectures the reason for this to be the high position of the horizontal stabilizer in relation to airflow around the wings.
Around one third of the airplanes tested by Fay had a slight tendency to skid during their first flights. This was easily eliminated by adjusting the trim tab on the rudder"
Now read this, the Allied POH for the Me-262 prepared by Allied test pilots:
http://www.zenoswarbirdvideos.com/Images/Me262/262PilotHandbook.pdf
Again under flying characteristics, surprise surprise, similar conclusions, great flying characteristics, no flutter in dives, utilizing the tail plane trim is too effective. Btw note the German air speed indicator lists TAS.
No where, I repeat no where do I see anything about poor handling! Infact I find quite the contrary, the handling of the a/c is praised by all who flew it!
You have a disturbing tendency to leap at sunshine and avoid the dark.
If Lindners debriefing, verified by Baur is BS - PROVE IT! They forgot more than you will ever know and their testimony and verification directly contradict what you say..
Give me a link to Lindners debriefing and Baur's verification Bill cause I can't find it.
No to reverse what you just said, are you saying that what LW test pilots Fritz Wendel Hans Fey as-well as the Allied test pilots are saying is BS ??
No I am not and have not - see specifically my comments extracted from Wendel below.
Ok, I think I understand the swept wing issue. (increased chord asside) Due to the sweep, the speed of the airflow over the wing is lower than it would be with a similar straight wing. It doesn't have anything to do with spanwise flow OVER the wing (and this doesn't even really occur at high speed and low AoA) but the airflow being spit with some flowing outward along the wing LE and the rest flowing over the wing. Thus the Mach number of the air flow experienced by the wing will be lower than that of the freestreem.
That is the theory as well as the way it is applied. The airflow 'sees' the correct airfoil in the chordwise component - but that component is Vfreestream*COS(angle of 1/4 chord sweep) and lower than V freestream
So a straight wing of 9% chord will have a lower critical mach number than a 35 degree swept wing of 11% chord of similar airfoil type. (despite the true chord length of both wings being the same)
Maybe but probably not. The analogy of using a thinner wing to approximate sweep is OK to approximate critical mach, but to work exactly right analytically (lift, lift distribution, drag, Moment. etc), the same airfoil with t/c =9% must have the same CL/CD and CMac statistics as the same airfoil with t/c = 11%to get everything else right
Also, the Komet apears to have a LE sweep of ~26 degrees. (the P-80 has one of ~12-15 degrees, though at the root it apears to be greater than 20 degrees. The vampire looks like ~15-18 degrees)
Additionally the Me 262's wing its self, while having a LE sweep of 18.5 degrees, only seems to have been swept back (outboard of the nacelles) ~11 degrees, to the change in actual thickness would be only ~2%. And this section is of 11% (at 40% chord) tapering to 9%.
Also the LE sweep of the tailplane is ~25 degrees and the fin's is ~45 degrees.
This implies that the tailplane, assuming near same t/c as wing, will remain sub critical after wing goes transonic. It is clear that the tail has three nice features. 1.) high enough to stay out of wake turbulence from wing, 2.) it was a slab tail giving more control force at high speed (also a danger) and 3.) it was designed to go into transonic after the wing - avoiding problems encountered with other high performance conventional a/c
However, I still don't know if the airfoil data for swept wing a/c is from a "head on" (unswept) perspective or if it's a measure of the true swept wing. (if it's the former, the 11% chord refrence to the F-86 would be in error)
Waynos reread the report plz, you can read that every a/c had to pass 1,000 to 1,050 km/h dive speed tests, which is well within the transonic region at 6-8km.
Great, a mod openly patronizing a member