What aircraft gun round had the flattest trajectory?

[Jabberwocky]

Probably because the general purpose bomb and Anti armour submunitions were more effective and less risky when engaging enemy tanks and or supply elements. Also, I imagine that when pilots were already complaining of the 15mms lack of punch against fighters, its a very difficult thing to engage a tank with what is percieved to be an underpowered gun and come away with some hope of sucess.

 

[Soren]

15mm MG151/15:

MV (AP): 850 m/s
MV (HE): 960 m/s

AP projectile weight: 72 gram (1,111.12 grains)
HE Projectile weight: 57 gram (879.64 grains)

AP projectile SD: .456
HE projectile SD: .361

20mm MG151/20:

MV (API): 720 m/s
MV (HET): 720 m/s
MV (HE"M"): 800 m/s

API projectile weight: 117 gram (1,805 grains)
HET projectile weight: 115 gram (1,774 grains)
HE"M" projectile weight: 92 gram (1,419 grains)

API projectile SD: .416
HET projectile SD: .409
HE"M" projectile SD: .327

30mm MK108:

MV (HE"M"): 505 m/s

HE"M" projectile weight: 330 gram (5,092 grains)

HE"M" projectile SD: .522

12.7mm M2 Browning:

MV (API): 890 m/s

API projectile weight: 43 gram (663.5 grains)

API projectile SD: .379

13mm MG131:

MV (API): 710 m/s
MV (APT): 710 m/s
MV (HET): 750 m/s

API projectile weight: 38 gram (586.4 grains)
APT projectile weight: 38.5 gram (594.1 grains)
HET projectile weight: 34 gram (524.7 grains)

API projectile SD: .321
APT projectile SD: .325
HET projectile SD: .287
_______________________________________________

Now for comparison's sake the German standard issue 7.92mm rifle round at 792 m/s with a FMJ boat-tail projectile at a weight of 12.8 grams (198 grains) with a SD of .292, has a BC of around .560-.580. That means that at 600m distance the velocity has dropped to around 509-517 m/s, and the time of flight to that distance is 0.94 sec. The time of flight out to 300m, which could be considered a medium range for opening fire on your target, will take the round 0.42 sec to reach, much quicker than any enemy fighter can react on being fired upon. At a 200m distance, which could be considered the normal range for opening fire on your target, the round will reach its target in 0.27 sec, and again this leaves the enemy fighter no chance of evading.

Now I think we can all agree that the 7.92mm rifle projectile didn't have the same ballistic qualities of the much heavier machinegun and cannon projectiles on the late war fighters, so if the 7.92mm round can hit without a problem out to 300m without leaving the enemy fighter a chance to evade, the cannons should do an even better job.

The gun above with the slowest MV is the 30mm MK108, however its projectile has a high SD, and all else being equal a higher SD means a higher BC. An educated and calculated guess of its flight time out to 300m gives a time of 0.63 sec, still fast enough for the enemy being unable to react and evade in time. So this gun is perfectly capable as a Fighter vs Fighter armament, and requires only a single hit to destroy its target. (And with the exception of usually not destroying its target with the first hit, the exact same applies for the MG151/20)

Now on to the question of which of the guns above has the flattest trajectory, it is clearly the 15mm MG151.

 

[delcyros]

I don´t think this explenation hits the point, Jabberwoky. According to may analysis the 15 mm MG151 has an initial armorpenetration at 0 degrees impact angle and zero distance (basic penetration) of 46mm for AP-rounds and even 60-62mm for APR rounds. The 20mm variant using API-rounds will not exceed 34 mm of basic penetration! The 15mm rounds will also keep their energy much better due to a higher SD and BC (nose shape). In this view the 20mm is underpowered, not the MG 151/15, at least against armoured targets. Against soft ones, the 20mm HE round carries nearly twice as much HE-ordenance and therefore is better.

Soren, Your datas sounds convinving. However, the 30mm round will suffer a drawback due to it´s worser ballistic shape. The BC is influenced a lot by this. Can You tell me how to calculate the time to range figures and, more important, the striking velocity at range figures (or the deceleration rate at range)?

 

[Jabberwocky]

I don´t think this explenation hits the point, Jabberwoky. According to may analysis the 15 mm MG151 has an initial armorpenetration at 0 degrees impact angle and zero distance (basic penetration) of 46mm for AP-rounds and even 60-62mm for APR rounds. The 20mm variant using API-rounds will not exceed 34 mm of basic penetration! The 15mm rounds will also keep their energy much better due to a higher SD and BC (nose shape). In this view the 20mm is underpowered, not the MG 151/15, at least against armoured targets. Against soft ones, the 20mm HE round carries nearly twice as much HE-ordenance and therefore is better.

However, when we look at German ground attack aircraft we see that it was the 20mm and not the 15mm that was fitted as the standard armament, even when the 15mm clearly has better AP perfomance. After the 109F1/F2, very few LuftWaffe planes carried the 15mm.

The HS-129 had a pair of MG151/20s
The HS-123, used primarily as a dive bomber, sometimes mounted a pair of 20mms.
The 190F, a specialised ground attack 190, mounted 2 MG 151/20s.

So the question is why? We know that the MG 151/15 had excellent AP performance. I'm sure that the LuftWaffe did as well. But they chose to stick with the 20mm or go for larger calibres like 30mm, 37mm, 50mm and even 75mm in specalised AT roles.

My guess is that the LuftWaffe judged the 20mm calibre to be more effective against soft targets and thought that was more important than effectiveness against armoured targets like tanks. When they were serious about using aircraft to knock out armour, they went to the 30mm or higher.

I'm not arguing that the 15mm would of been ineffective. I'm just trying to work out the logic of fitting the 20mm as standard over the 15mm in ground attack roles, where the planes are more likely to run into armour.

 

[Soren]

Soren, Your datas sounds convinving. However, the 30mm round will suffer a drawback due to it´s worser ballistic shape. The BC is influenced a lot by this.

What your talking about is called the "Form Factor" or FF, and no the 30mm HE"M" projectile doesn't necessarily have a worse BC because of its FF, although it is true that some of the HE"M" projectiles aren't ballistically very efficient compared to their size and SD(Infact none of them really are, but some are definitely worse than others), which is because of their FF. However not all the HE"M" projectiles have such a inefficient FF.

Here you can see two different examples of the 30mm HE"M" projectiles used by the Mk108(The one to the left obviously the most efficient ballistically) :

Can You tell me how to calculate the time to range figures and, more important, the striking velocity at range figures (or the deceleration rate at range)?

I used Norma's own ballistics program to calculate the trajectory and flight time of the 7.92mm projectile(You can choose yourself between Metric or Imperial units): http://www.norma.cc/sida/eng/index.html

 

[delcyros]

I sadly couldn´t acces Norma.
From what I understand, the trajectory can be calculated via sectional density and form factor.
Here is what I got to this moment (am not sure if all is correct):
metric measurement:
W= projectile weight in grams x 1.422 (this seems to be a constantum but why?)
D(x2)= square of the calibre in mm
SD= W/D(x2)
The higher the SD the better the velocity retention (assuming an equal FF)
The FF (form factor) is more difficult to extrapolate. I lean on empiric datas:
FF=
flat nosed lead: 0.8
round nosed lead: 0.9
round nose-jacketed: 1.0
semi-pointed-soft point: 0.9-1.1
pointed soft point (depending on sharpness): 1.2-1.6
pointed full jacket: 1.5-1.8
pointed full jacket and boat tailed: 2.0
The FF differs in supersonic and subsonic speeds, so a drop under Mach 1.3 will cause FF differences of the same projectile.
The result of SD x FF (correct relation?) gives the BC.
The BC will give the true deceleration rate but in how far?
(for each 100m distance): BC=0.15--0.20--0.25--0.30--0.35--0.40--0.45--0.50--0.55--0.60
%=-25----18----14---11.5--9.5----8-----7-----6.5---?------?
I still have no clue how the deceleration rate develops at higher BC (and what formula is used for calculation of speed loss) and I also don´t know why the atmosspheric factor isn´t involved (high altitude=low air density=higher speed retention and vice versa in low altitudes).
Jabberwoky, I totally agree with you. No ww2 20mm gun present any harm for main battle tanks and soft targets were more often encountered anyway. Had they deal with tanks, they generally preferred bombs, heavy cannons and/or rockets.

 

[Soren]

I sadly couldn´t acces Norma.

Try this one then: http://www.biggameinfo.com/BalCalc.aspx

From what I understand, the trajectory can be calculated via sectional density and form factor.
Here is what I got to this moment (am not sure if all is correct):
metric measurement:
W= projectile weight in grams x 1.422 (this seems to be a constantum but why?)
D(x2)= square of the calibre in mm
SD= W/D(x2)
The higher the SD the better the velocity retention (assuming an equal FF)
The FF (form factor) is more difficult to extrapolate. I lean on empiric datas:
FF=
flat nosed lead: 0.8
round nosed lead: 0.9
round nose-jacketed: 1.0
semi-pointed-soft point: 0.9-1.1
pointed soft point (depending on sharpness): 1.2-1.6
pointed full jacket: 1.5-1.8
pointed full jacket and boat tailed: 2.0
The FF differs in supersonic and subsonic speeds, so a drop under Mach 1.3 will cause FF differences of the same projectile.
The result of SD x FF (correct relation?) gives the BC.
The BC will give the true deceleration rate but in how far?
(for each 100m distance): BC=0.15--0.20--0.25--0.30--0.35--0.40--0.45--0.50--0.55--0.60
%=-25----18----14---11.5--9.5----8-----7-----6.5---?------?
I still have no clue how the deceleration rate develops at higher BC (and what formula is used for calculation of speed loss) and I also don´t know why the atmosspheric factor isn´t involved (high altitude=low air density=higher speed retention and vice versa in low altitudes).

Accurately calculating the trajectory and deceleration rate by hand is impossible if you haven't got the exact specifications of the projectile as-well conducted real life firing tests.

Now I don't exactly remember the usual drag function of a bullet like the 7.92mm FMJ-BT projectile, but IIRC it is G7. (The standard used for all projectiles being G1, which however is not accurate for FMJ-BT projectiles)

 

[Erich]

Soren your diagrahm shows the Incendiary and also Tracer round with Glimmspur on the left and the standard HE Minengeschoss on the right with blunt head

there are at least 8 rounds used for the Luftwaffe's arsenal including at leat 4-5 different practice rounds in the 3cm line-up

By the way your copyrighted image comes from the Bf 109 book by Robert Grinsell via Crown publishers, NY

 

[Soren]

Thanks for the correction. Do you have any pictures of the different rounds Erich ? (Would be higly appriciated)

 

[delcyros]

The link works fine, thanks.
I wonder why nowhere in the net is a basic calculating program for trajectory and deceleration (the link offers solutions for up to 20 mm rounds).
Thanks again.